根据列的范围分组汇总的是_根据列的范围分组汇总的Sql存储过程

更新时间:2018-05-21    来源:公务员类考试    手机版     字体:

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  1.需求说明
  有如下表数据:
  ID       NUM
  ----------- -----------
  1        2
  2        3
  3        2
  4        2
  5        12
  6        2
  7        1
  8        5
  9        1
  10       1
  11       1
  输入分组参数,比如输入 "2,5,8,10" ,实现按 ID<=2,2<ID<=5,5<ID<=8,8<ID<=10,ID>10 分组查询,要得到下面的数据:
  groupdata  num
  ---------- -----------
  id<=2     5
  2<id<=5   16
  5<id<=8   8
  8<id<=10   2
  id>10     1
  2.存储过程如下:
  --测试数据
  create table TestData(ID int,NUM int)
  insert TestData select 1,2
  union all select 2,3
  union all select 3,2
  union all select 4,2
  union all select 5,12
  union all select 6,2
  union all select 7,1
  union all select 8,5
  union all select 9,1
  union all select 10,1
  union all select 11,1
  go
  create proc spgroupcol
  @numlist varchar(1000)
  as
  set nocount on
  declare @t table(id int identity,groupdata varchar(10),a int,b int)
  declare @i int,@pnum varchar(10),@j int
  select @i=charindex(",",@numlist)
  ,@pnum=left(@numlist,@i-1)
  insert @t select "id<="+@pnum,null,@pnum
  while @i>=1

  begin
  select @numlist=substring(@numlist,@i+1,len(@numlist)-@i)
  select @j=charindex(",",@numlist) ;  
  if @i=@j
  begin
  insert @t select @pnum+"<id<="+substring(@numlist,0,@i),@pnum,substring(@numlist,0,@i)
  select @pnum=left(@numlist,@i-1);
  end
  else
  begin
  insert @t select @pnum+"<id<="+substring(@numlist,0,@i+1),@pnum,substring(@numlist,0,@i+1)
  select @pnum=left(@numlist,@i);
  end
  select @i=charindex(",",@numlist) ;
  end
  insert @t select "id>"+@numlist,@numlist,null
  select b.groupdata,num=sum(a.num)
  from TestData a,@t b
  where case 
  when b.a is null then case when a.id<=b.b then 1 else 0 end
  when b.b is null then case when a.id>b.a then 1 else 0 end
  else case when a.id>b.a and a.id<=b.b then 1 else 0 end
  end=1
  group by b.groupdata
  order by min(b.id)
  go
  spgroupcol "2,5,8,10"
  drop table TestData
  sql存储过程的单步调试要在Vs2008中,服务器管理器中连接上数据库,找到存储过程右键单步调试。

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